Cubs rout Indians 9-3, send World Series to deciding Game 7

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CLEVELAND, OH - NOVEMBER 01: Anthony Rizzo #44 of the Chicago Cubs and Kris Bryant #17 celebrate with teammates after defeating the Cleveland Indians 9-3 to win Game Six of the 2016 World Series at Progressive Field on November 1, 2016 in Cleveland, Ohio. (Photo by Gregory Shamus/Getty Images)

 

CLEVELAND (AP) — Addison Russell hit a grand slam and drove in a record-tying six runs, leading the Chicago Cubs over the Cleveland Indians 9-3 Tuesday night and forcing the World Series to a deciding Game 7.

Indians ace Corey Kluber, dominant while winning Games 1 and 4, starts again on short rest Wednesday night at home against big league ERA leader Kyle Hendricks.

The Cubs are trying to overcome a 3-1 Series deficit for their first championship since 1908. The Indians haven’t won it all since 1948.

Kris Bryant had four hits for Chicago and homered for the second straight game. Anthony Rizzo also homered.

The Cubs got two gift runs in the first inning when Russell’s pop fly dropped between two outfielders.

Jake Arrieta cruised to the win, adding to his victory in Game 2. Closer Aroldis Chapman got four outs before exiting in the ninth.

Russell’s slam in the third made it 7-0. He tied Albert Pujols, Hideki Matsui and Bobby Richardson for most RBIs in a Series game.

 

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